Answer :
-5 - 5β3 i = -5 (1 + β3 i )
We have modulus
|-5 (1 + β3 i )| = 5 β(1Β² + (β3)Β²) = 5β4 = 10
and argument
arg(-5 - 5β3 i ) = Ο - arctan(β3) = 2Ο/3
(we subtract from Ο because the given complex number lies in the third quadrant of the complex plane, whereas the arctan function only returns angles between -Ο/2 and Ο/2)
so that the polar form of the number is
-5 - 5β3 i = 10 exp(2Ο/3 i )
By DeMoivre's theorem, we have
(-5 - 5β3 i )Β³ = 10Β³ exp(3 Γ 2Ο/3 i ) = 1000 exp(2Οi ) = 1000