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Answer :

Answer:

b = [tex]\frac{1+2a}{3a-1}[/tex]

Step-by-step explanation:

Given

a = [tex]\frac{b+1}{3b-2}[/tex] ( multiply both sides by 3b - 2 )

a(3b - 2) = b + 1 ← distribute left side

3ab - 2a = b + 1 ( subtract b from both sides )

3ab - b - 2a = 1 ( add 2a to both sides )

3ab - b = 1 + 2a ← factor out b from each term on the left side

b(3a - 1) = 1 + 2a ( divide both sides by 3a - 1 )

b = [tex]\frac{1+2a}{3a-1}[/tex]

Manissaha129go

Answer:

[tex]→a = \frac{(b + 1)}{(3b - 2)} \\ a(3b - 2) = (b + 1) \\ 3ab - 2a = b + 1 \\ 3ab - b = 2a + 1 \\ b(3a - 1) =( 2a + 1) \\ \boxed{b = \frac{(2a + 1)}{(3a - 1)} }✓[/tex]

  • b = (2a+1)/(3a-1) is the right answer.

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