Answer:
[tex]\left(x+3\right)\left(x-3\right)[/tex]
Step-by-step explanation:
[tex]x^2 -9[/tex]
To factor an integer, we need to divide it by the ascending sequence of primes (2, 3, 5). The number of times each prime divides the original integer becomes its exponent. [tex]3^{2} =9[/tex]
Now, we need to factor this expression by applying the difference of two squares rule:
[tex]A^{2} -B^{2} =(A+B)(A-B)[/tex]
A= x and B= 3
[tex](x+3)(x-3)[/tex]
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