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Answer :

Find Empirical mass.

[tex]\\ \bullet\sf\longmapsto C_2H_3O_2[/tex]

[tex]\\ \bullet\sf\longmapsto 2(12u)+3(1u)+2(16u)[/tex]

[tex]\\ \bullet\sf\longmapsto 24u+3u+32u[/tex]

[tex]\\ \bullet\sf\longmapsto 59g/mol[/tex]

Now Divide it by Molecular Mass..

[tex]\\ \bullet\sf\longmapsto \dfrac{118}{59}[/tex]

[tex]\\ \bullet\sf\longmapsto 2[/tex]

Now molecular formula

[tex]\\ \bullet\sf\longmapsto 2(C_2H_3O_2)[/tex]

[tex]\\ \bullet\sf\longmapsto C_4H_6O_4[/tex]

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