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Answer :

Triangular case:-

  • B=9cm
  • H=6cm

[tex]\\ \bullet\sf\leadsto Area=\dfrac{1}{2}BH[/tex]

[tex]\\ \bullet\sf\leadsto Area=\dfrac{1}{2}(6)(9)[/tex]

[tex]\\ \bullet\sf\leadsto Area=3(9)[/tex]

[tex]\\ \bullet\sf\leadsto Area=27cm^2[/tex]

Area of both triangular sides=27+27=54cm^2

Rectangular case;-

  • L=7cm
  • B=5cm

[tex]\\ \bullet\sf\leadsto Area=LB[/tex]

[tex]\\ \bullet\sf\leadsto Area=7(5)[/tex]

[tex]\\ \bullet\sf\leadsto Area=35cm^2[/tex]

Area of 3sides=35(3)=105cm^2

Now

[tex]\\ \bullet\sf\leadsto TSA=105+54=159cm^2[/tex]

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