help.? geometry basics homework 2: segment addition postulate

The value of x is 3 given that ST = 8x + 11 and TU = 12x-1
The point that bisects a line divides the line into two equal parts
If T is the midpoint of SU, the following are true:
Given the following
ST = 8x + 11
TU = 12x-1
Since ST = TU
8x+11 = 12x-1
8x - 12x = -1 - 11
-4x = -12
x = 12/4
x = 3
Hence the value of x is 3 given that ST = 8x + 11 and TU = 12x-1
Learn more here: https://brainly.com/question/17204733
Answer:
QS = 34
Step-by-step explanation:
Question: 12
1. 5x - 3 = 21 - x
2. 6x = 24
3. x = 4
so; 5(4)-3 = 17 and 21-4=17
Which means 17+17 = QS
QS=34