How much potential energy is stored in the spring that is stretched 1.50m and has a
spring constant of 350.

Answer:
393.75J
Explanation:
The potential energy stored in a spring is given by the formula:
E = (k•x²)/2 where E is the energy, k is the spring constant and x is the stretched distance, so:
E = (350•1.5²)/2 = 393.75J