👤

Answer :

Solution:-

  • a=Carbon(c)
  • b=Nitrogen ion(N+)
  • c=Oxygen ion(O-)

Now

#1

Let's look at the EC of carbon(Z=6)

[tex]\\ \tt\longmapsto 1s^22s^22p^2[/tex]

  • Valency is 4

Now.

3 electrons are shared(1 with H_3C and 2 with N+)

Hence

Electron left unshared=4-3=1

#2

Lets look at EC of Nitrogen(N),Z=7

[tex]\\ \tt\longmapsto 1s^22s^22p^3[/tex]

  • Valency is 3
  • It has already shared 3 electrons

But

Its Cation i.e N+

  • Hence 1 electron it donated .Now it has valency 4

Hence

Electron left unshared=4-3=1

#3

Lets look at EC of Oxygen(Z=8)

[tex]\\ \tt\longmapsto 1s^22s^22p^4[/tex]

  • Valency =2

But it is anion hence 1electron required more which us bonded

Hence

Number of electrons left unshared=0

Go Teaching: Other Questions