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About how many electrons are in 30 grams of water (H2O)?

The answer is 10^25, i took a lucky guess i just want to know how to find that.

Answer :

LammettHashgo

Hydrogen (H) has a molar mass of about 1.007 g/mol and has 1 electron.

Oxygen (O) has a molar mass of about 15.999 g/mol and has 8 electrons.

Then water (H₂O) has a total molar mass of about 18.015 g/mol and has 10 electrons.

30 g of water is the mass of

(30 g) × (1/18.015 mol/g) ≈ 1.66528 mol

of water. Recall that 1 mole is around 6.022 × 10²³ molecules (i.e. Avogadro's number). So 30 g of water is the mass of approximately 1.00285 × 10²⁴ molecules of water.

If each molecule contains 10 electrons, then 30 g of water contains 1.00285 × 10²⁵ ≈ 10²⁵ electrons.

Dsdrajlingo

In 30 g of water, there are 1.0 × 10²⁵ electrons.

We want to calculate the number of electrons in 30 grams of water. We need to consider the following relationships.

  • The molar mass of water is 18.02 g/mol.
  • 1 mole of molecules of water contains 6.02 × 10²³ molecules of water (Avogadro's number).
  • 1 molecule of water has 10 electrons (see attached Lewis diagram).

[tex]30 g \times \frac{1mol}{18.02g} \times \frac{6.02 \times 10^{23}molecule }{1mol} \times \frac{10electron}{1molecule} = 1.0 \times 10^{25} electron[/tex]

In 30 g of water, there are 1.0 × 10²⁵ electrons.

Learn more about Avogadro's number here: https://brainly.com/question/1445383

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