Answer :
There is 18.4 % oxygen in the compound, 12.8 % hydrogen in the compound and 69.0 % carbon in the compound.
The molecular formula of the compound is; C10H22O2. From this, we can calculate the molar mass of the compound as follows;
Molar mass = 10(12) + 22(1) + 2(16) = 120 + 22 + 32 = 174 g
Percent of oxygen in the compound = 32.00 g/174 g × 100/1 = 18.4 %
Percent of hydrogen in the compound = 22.22 g/174 g × 100/1 = 12.8 %
Percent of carbon in the compound = 120.10 g/174 g × 100/1 = 69.0 %
Hence, there is 18.4 % oxygen in the compound, 12.8 % hydrogen in the compound and 69.0 % carbon in the compound.
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