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Answer :

Eduard22slygo

The mass percent of nitrogen in C₁₄H₁₉NO₂ is 6%

  • We'll begin by calculating the molar mass of C₁₄H₁₉NO₂ . This can be obtained as follow:

Molar mass of C₁₄H₁₉NO₂ = (12×14) + (1×19) + 14 + (16×2)

= 233 g/mol

  • Next, we shall determine the mass of N in C₁₄H₁₉NO₂. This can be obtained as follow:

Mass of N in C₁₄H₁₉NO₂ = 14 g/mol

  • Finally, we shall determine the mass percent of nitrogen, N, in C₁₄H₁₉NO₂. This can be obtained as follow:

Molar mass of C₁₄H₁₉NO₂ = 233 g/mol

Mass of N in C₁₄H₁₉NO₂ = 14 g /mol

Percentage of N =?

[tex]Percent = \frac{mass of element}{mass of compound} * 100\\\\= \frac{14}{233} * 100[/tex]

= 6%

Therefore, the mass percent of nitrogen in C₁₄H₁₉NO₂ is 6%

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