Answer :
Step-by-step explanation:
x²+2x=-1
x²+2x+1=0
x²+x+x+1=0
x(x+1)+1(x+1)=0
(x+1)(x+1)=0
(x+1)²=0
x+1=0
x=-1
let's solve :
- [tex] {x}^{2} + 2x + 1 = 0[/tex]
- [tex]x {}^{2} + x + x + 1 = 0[/tex]
- [tex]x(x + 1) + 1(x + 1) = 0[/tex]
- [tex](x + 1)(x + 1) = 0[/tex]
- [tex](x + 1) {}^{2} = 0[/tex]
- [tex]x + 1 = 0[/tex]
- [tex]x = - 1[/tex]
hence, value of x = -1