Answer:
Step-by-step explanation:
(-2 , 3) & (-8 , 1)
[tex]Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\dfrac{1-3}{-8-[-2]}=\dfrac{1-3}{-8+2}\\\\=\dfrac{-2}{-6}\\\\=\dfrac{1}{3}[/tex]
m1 = 1/3
Slope of the perpendicular line to the given line = -1/m1 = -1 ÷ [tex]\frac{1}{3}[/tex] = [tex]-1*\frac{3}{1}=-3[/tex]
Equation of the perpendicular line: y =mx +b
[tex]y = -3x + b[/tex]
Plugin x = -5 & y =1
1 = -3*(-5) + b
1 = 15 + b
1 - 15 = b
b = -14
Equation of the line : y = -3x - 14
