Please help with Q8B thank you!

Answer:
[tex]\frac{1}{15}[/tex] (3x + 2)(5x - 2)
Step-by-step explanation:
x² + [tex]\frac{4}{15}[/tex] x - [tex]\frac{4}{15}[/tex] ← factor out [tex]\frac{1}{15}[/tex] from each term
= [tex]\frac{1}{15}[/tex] (15x² + 4x - 4) ← factor using the result from (a)
= [tex]\frac{1}{15}[/tex] (3x + 2)(5x - 2)