Answer :
Answer:
=
β
7
3
=
β
7
Step-by-step explanation:
=
β
Β±
2
β
4
β
2
x={b}}^{2}-4{a}}{2{a}}}
x=2aβbΒ±b2β4acββ
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
3
2
+
2
8
+
4
9
=
0
3x^{2}+28x+49=0
3x2+28x+49=0
=
3
a={3}}
a=3
=
2
8
b={28}}
b=28
=
4
9
c={129}{49}}
c=49
=
β
2
8
Β±
2
8
2
β
4
β
3
β
4
9
β
2
β
3
=
β
2
8
Β±
1
4 over
6
=
β
2
8
+
1
4
6
x={-28+14}{6}
x=6β28+14β
=
β
2
8
β
1
4
=
β
7
3
x=-{7}{3}
x=β37β
=
β
7
=
β
7
3
=
β
7