Answer :
Solution:
[tex]given \: \: a=2,b=-3,c=1,d=-2 \\ then \: \: d + 2c - (3a - 2b) \\ = ( - 2) + 2(1) - (3 \times 2 - 2 \times -3) \\ = - 2 + 2 - (6 + 6) \\ = 0 - 12 \\ = - 12[/tex]
Answer:
-12
Hope it helps..
ray4918 here to help..
Gracias!!
[tex]given \: \: a=2,b=-3,c=1,d=-2 \\ then \: \: d + 2c - (3a - 2b) \\ = ( - 2) + 2(1) - (3 \times 2 - 2 \times -3) \\ = - 2 + 2 - (6 + 6) \\ = 0 - 12 \\ = - 12[/tex]
-12
ray4918 here to help..
Gracias!!