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Answer :

Solution:

[tex]f(x) = \sqrt{ {x}^{2} } - 5 \\ = > f(4) = \sqrt{ {(4)}^{2} } - 5 \\ \: \: \: \: \: \: \: \: \: \: = \sqrt{16 } - 5 \\ = 4 - 5 \\ = - 1 \\ or \\ = - 4 - 5 \\ = - 9[/tex]

Answer:

-1 or -9

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