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Answer :

Mhanifago

Answer:

  • ₹ 3060.40

Step-by-step explanation:

Given:

  • Principal P = ₹ 50000
  • Interest rate r = 8% PA
  • Time t = 9 months = 9*1/12 years = 3/4 years
  • Number of compounds per year n = 4

The amount of interest:

  • [tex]I = P*(1+r/n)^{nt} - P[/tex]
  • [tex]I = 50000*(1+8/4*1/100)^{4*3/4}-50000= 3060.40[/tex]
ItzMeÆXOgo

Answer:

Rs. 3060.4

Step-by-step explanation:

[tex]\sf{ A = P \times (1 + \frac{r}{n})^{nt} }[/tex]

[tex]\sf{ A = 50000 \times (1 + \frac{8}{4} \times \frac{1}{100} )^{4 \times \frac{3}{4}} }[/tex]

[tex]\sf{ A =53060.4 }[/tex]

.

compound interest

[tex]\sf{ Ci = A - P}[/tex]

[tex]\sf{ Ci = 53060.4 - 50000}[/tex]

[tex]\sf{ Ci = 3060.4 }[/tex]

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