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Answer :

Onyebuchinnajigo

The acceleration of the bus for the given velocities and time of motion is 6 m/s².

The given parameters;

  • Initial speed of the bus, u = 24 m/s
  • Final sped of the bus, v = 6 m/s
  • Time of motion of the bus, t = 3 s

Acceleration is defined as the time rate of change of velocity.

Acceleration can be uniform if the change in velocity occurs at equal time interval.

The acceleration of the bus for the given velocities and time of motion is calculated as;

[tex]a = \frac{v-u}{t} \\\\a = \frac{24-6}{3} \\\\a = 6 \ m/s^2[/tex]

Thus, the acceleration of the bus for the given velocities and time of motion is 6 m/s².

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