Kinetic energy is the energy of a body, when in motion.
The kinetic energy of ball 1 is greater than the kinetic energy of ball 2.
The question is incomplete, as the table is not given; so, I will give a general explanation.
The kinetic energy of a body is:
[tex]\mathbf{KE = \frac 12mv^2}[/tex]
Where:
[tex]\mathbf{v \to velocity}[/tex]
[tex]\mathbf{m \to mass}[/tex]
Assume, the following parameters for ball 1
[tex]\mathbf{m= 1kg}[/tex]
[tex]\mathbf{v= 2ms^{-1}}[/tex]
So, the kinetic energy of ball 1 is:
[tex]\mathbf{KE = \frac 12 \times 1 \times 2^2}[/tex]
[tex]\mathbf{KE = \frac 12 \times 1 \times 4}[/tex]
[tex]\mathbf{KE = 2J}[/tex]
Assume, the following parameters for ball 2
[tex]\mathbf{m= 2kg}[/tex]
[tex]\mathbf{v= 1ms^{-1}}[/tex]
So, the kinetic energy of ball 2 is:
[tex]\mathbf{KE = \frac 12 \times 2 \times 1^2}[/tex]
[tex]\mathbf{KE = \frac 12 \times 2 \times 1}[/tex]
[tex]\mathbf{KE = 1J}[/tex]
Using the assumed parameters, we can conclude that ball 1 has a higher kinetic energy than ball 2.
Read more about kinetic energy at:
https://brainly.com/question/12669551
