Answer :
The expected number of a distribution is its mean.
- The expected number of Americans who are satisfied with the way things are going in the United States is 6
- The standard deviation of Americans who are satisfied with the way things are going in the United States is 2.05
The given parameters are:
[tex]\mathbf{p = 30\%}[/tex] --- the proportion that are satisfied
[tex]\mathbf{n = 20}[/tex] --- the sample size
(a) The expected number that are satisfied
This is calculated using:
[tex]\mathbf{E(x) = np}[/tex]
So, we have:
[tex]\mathbf{E(x) = 20 \times 30\%}[/tex]
[tex]\mathbf{E(x) = 6}[/tex]
The expected number of Americans who are satisfied with the way things are going in the United States is 6
(b) The standard deviation of those that are satisfied
This is calculated using:
[tex]\mathbf{\sigma = \sqrt{n \times p \times (1 - p)}}[/tex]
So, we have:
[tex]\mathbf{\sigma = \sqrt{20 \times 30\% \times (1 - 30\%)}}[/tex]
[tex]\mathbf{\sigma = \sqrt{20 \times 30\% \times 70\%}}[/tex]
[tex]\mathbf{\sigma = \sqrt{4.2}}[/tex]
[tex]\mathbf{\sigma = 2.05}[/tex]
The standard deviation of Americans who are satisfied with the way things are going in the United States is 2.05
Read more about expected value and standard deviations at:
https://brainly.com/question/17088771