The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is: [tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]
- The feeder can hold 30 baseballs, when full
The given parameters are:
[tex]\mathbf{Initial = \frac 16x}[/tex] ------ 1/6 full
[tex]\mathbf{Additional = 15}[/tex] --- baseballs added
[tex]\mathbf{Final = \frac 23x}[/tex] ---- 2/3 full
So, the equation that represents the problem is:
[tex]\mathbf{Initial + Additional = Final}[/tex]
So, we have:
[tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]
The number of baseballs it can hold is calculated as follows:
[tex]\mathbf{\frac 16x + 15 = \frac 23x}[/tex]
Multiply through by 6
[tex]\mathbf{x + 90 = 4x}[/tex]
Collect like terms
[tex]\mathbf{4x - x = 90 }[/tex]
[tex]\mathbf{3x = 90 }[/tex]
Divide through by 3
[tex]\mathbf{x = 30 }[/tex]
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
https://brainly.com/question/20337104