Answer:
- R1, R4: 1.3433 V
- R2: 0 V
- R3: 6.3134 V
Explanation:
The resistor R2 is shorted out, so is not in the circuit. The remaining resistors are in a series circuit with a total resistance of ...
R1 +R3 +R4 = 1k +4.7k +1k = 6.7k
The current is the ratio of the applied voltage to this total resistance:
I = V/R = (9 v)/(6.7k) ≈ 1.3433 mA
The voltage across each resistor is the product of this current value and the resistance:
R1 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts
R2 voltage = 0
R3 voltage = (4.7 kΩ)(1.3433 mA) = 6.3134 volts
R4 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts
