We have that with v_1 =v this goes to show that the velocity of the bigger block after the collision takes place is v
From the question we are told
Suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?
Generally the equation for Momentum is mathematically given as
P=mv
Therefore
[tex]m_1v_2=m_2v_2[/tex]
Hence
[tex]v_1=\frac{m_2v_2}{m_1}[/tex]
Therefore
[tex]v_1=\frac{mv_2}{2m}\\\\v_1=\frac{v_2}{2}[/tex]
Hence
[tex]2v+v=v_1+v_2\\\\v_1=v[/tex]
Now
with v_1 =v this goes to show that the velocity of the bigger block after the collision takes place is v
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