Answer :
Step-by-step explanation:
a and b are not integers
[tex] {x}^{2} + 6x + 13 = 0 \\ x = - 3 \pm2i[/tex]
[tex]a \: \in \mathbb{C}[/tex]
[tex]b \: \in \mathbb{C}[/tex]
Step-by-step explanation:
a and b are not integers
[tex] {x}^{2} + 6x + 13 = 0 \\ x = - 3 \pm2i[/tex]
[tex]a \: \in \mathbb{C}[/tex]
[tex]b \: \in \mathbb{C}[/tex]