The force constant of this stretched spring is equal to 200 N/m.
Given the following data:
Conversion:
Extension = 4 centimeters = [tex]\frac{4}{100} = 0.04\; meters[/tex]
To calculate the force constant of a stretched spring, we would apply Hooke's law:
First of all, we would determine the force acting on the spring.
[tex]Force = mg\\\\Force = 0.8 \times 10[/tex]
Force = 8 Newton
Mathematically, Hooke's law force is given by the formula:
[tex]F = ke[/tex]
Where:
Substituting the given values into the above formula, we have:
[tex]8 = k\times 0.04\\\\k = \frac{8}{0.04}[/tex]
Spring constant, k = 200 N/m
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