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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.2°. If skyscraper B is 1436 feet tall, how far apart are the two
skyscrapers? Assume the bases of the two buildings are at the same elevation

Answer :

Answer:

we draw triangle and see it 90°. As we know height of building B and inclination angle we can get the lenght of base of the triangle.

L- distance

tan14,6=1431/L

L=1431/tan14.6 = 5493.69ft

:)

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