The static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex].
The given parameters;
- mass of the block, = M
- coefficient of static friction in section 1, = [tex]\mu_s_1[/tex]
- angle of inclination of the plane, = θ
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
[tex]F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta[/tex]
Thus, the static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex]
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