When b = 3 and c = 4, b⁵c⁶/b³c³

Substitute the variables for the numbers. Then solve.
b⁵ = 3⁵ = 243
c⁶ = 4⁶ = 4096
b³ = 3³ = 27
c³ = 4³ = 64
(243)(4096)/(27)(64) = 576
Answer:
simplify the powers, so b^(5-3) * c^(6-3) =
b^2 * c^3 = 3^2 * 4^3 =
9 * 64 = 576