Chris wanted to transform the graph of the parent function mc018-1. Jpg by horizontally compressing it so that it has a period of mc018-2. Jpg units, horizontally translating it mc018-3. Jpg units to the right, and vertically translating it 1 unit up. To do so, he graphed the function mc018-4. Jpg, as shown. What did he do wrong?.

Answer: The answer is C: He graphed the function y=cot(2x-pi/4)+1 correctly but it was not the right function to graph. He should have graphed y=cot(2x-pi/2)+1.

Explanation:

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Martebigo Martebigo · Answer 2

There are different ways to graph the transformation of a parent function. The fact remains that Chris did rightly graphed the function y = cot(2x - pi/4) + 1.

Chris did not graph the right function. The best he could have done is graphed y = cot(2x - pi/2) + 1.

Why should Chris graphed y = cot(2x - pi/2) + 1.

The graphed y = cot(2x - pi/2) + 1 is right because; pi/2, implies that b must be equal to 2 (this only apply when one use the period equation for tan and cot, pi/b, For pi/b to be equivalent to pi/2, b must be 2).

The right equation is graphed y = cot(2x-pi/2)+1 because through the division of the two numbers out of the equation that is inside the parenthesis.

Then from the above, you get the graph of y = cot2(x-pi/4)+1, which is the correct equation Christ should have graphed.

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