help need pls anewer 1-4

Answer:
1. width is w. length is w + 26
2.
[tex]w \times (w + 26) < 2040[/tex]
3. the width must be less than 34
4. sure, if the width is 10, then the area is 360
Step-by-step explanation:
[tex]w \times (w + 26) < 2040[/tex]
1
Answer:
Step-by-step explanation:
1) Width = w ft
Length = ( w + 26 ) ft
2) Area of floor = length *width
(w + 26)*w < 2040
w*w + 26*w < 2040
w² + 26w - 2040 < 0
3) w² - 34w + 60w - 2040 < 0
w(w - 34) + 60(w - 34) < 0
(w -34)(w + 60) < 0
Ignore w +60 as width wont have a negative value.
w - 34 < 0
w < 34
l = 33 + 26 = 59
Width = 33 and length= 59
Area = length * width = 33 * 59 = 1947 sq. ft
Area ≤ 1947
4) Yes.
If width = 10 , length = 26 + 10 = 36
36* 10 = 360 sq. ft.
So, if it possible to have a n area of 360 sq. ft