The number of mole in the container at 1.8 atm with a temperature of 270 K is 0.162 mole.
From the question given above, the following data were obtained:
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) = 2 L
Pressure (P) = 1.8 atm
Temperature (T) = 270 K
Number of mole (n) =?
Using the ideal gas equation, we can obtain the number of mole in the container as illustrated below:
PV = nRT
1.8 × 2 = n × 0.0821 × 270
3.6 = n × 22.167
Divide both side by 22.167
n = 3.6 / 22.167
n = 0.162 mole
Therefore, the number of mole in the container is 0.162 mole
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