Answer :
We want to find the slope of the line that connects points C' and D'. We will find that the slope is -3/7.
First, we start with the points:
- C = (-5, 8)
- D = (2, 5)
Now we create points C' and D' by translating points C and D to the left by 6 units, this means that we need to subtract 6 in the x-value of each point, so we will have:
- C' = (-5, 8) + (-6, 0) = (-5 - 6, 8) = (-11, 8)
- D' = (2, 5) + (-6, 0) = (2 - 6, 5) = (-4, 5)
And we know that if a line passes through points (x₁, y₁) and (x₂, y₂) the slope is given by:
[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Then the slope that connects points C' and D' is:
[tex]a = \frac{5 - 8}{2 - (-5)} = \frac{-3}{7}[/tex]
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