The angle measure for the inclined ramp needed to keep the larger weight from sliding down the ramp is 42⁰.
The given parameters;
- mass of the small block, m = 2 lb = 0.91 kg
- mass of the larger block, = M = 3 lb = 1.36 kg
The normal force on the larger weight (3 lb) is calculate as;
[tex]F_n = Mgcos(\theta)[/tex]
The net force on the larger weight is calculated as;
[tex]Mgsin(\theta) - T = 0[/tex]
where;
- T is the tension on the wire due to the smaller weight pulling up the 3 lb weight.
T = mg
[tex]Mgsin(\theta) - mg = 0\\\\(1.36\times 9.8)sin\theta \ - \ (0.91 \times 9.8) = 0\\\\13.328 sin(\theta) = 8.918\\\\sin(\theta) = \frac{8.918}{13.328} \\\\sin(\theta) = 0.669\\\\\theta = sin^{-1} (0.669)\\\\\theta = 42\ ^0[/tex]
Thus, the angle measure for the inclined ramp needed to keep the larger weight from sliding down the ramp is 42⁰.
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