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Answer :

LammettHashgo

By the product and chain rules,

f'(x) = g(h(x)) + x g'(h(x)) h'(x)

Then

f'(3) = g(h(3)) + 3 g'(h(3)) h'(3)

f'(3) = g(4) + 3 g'(4) (-2)

f'(3) = g(4) - 6 g'(4)

f'(3) = 2 - 6(3)

f'(3) = -16

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