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A 4.0 kg dog runs from one end of a 21 kg canoe to the other, a distance of 4.9 m. Assuming negligible water resistance, how far does the canoe move in metres?

Answer :

Onyebuchinnajigo

The distance traveled by the canoe in the water is 0.93 m.

The given parameters;

  • mass of the dog, m = 4.0 kg
  • mass of the canoe, = 21 kg
  • distance traveled by the dog, d = 4.9 m

Apply the principle of conservation of linear momentum to determine the distance traveled by the canoe;

[tex]m_1v_1 = m_2 v_2\\\\m_1(\frac{d_1}{t} ) = m_2(\frac{d_2}{t} )\\\\4(4.9) = 21(d_2)\\\\d_2 = \frac{4(4.9)}{21} \\\\d_2 = 0.93 \ m[/tex]

Thus, the distance traveled by the canoe in the water is 0.93 m.

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