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Answer :

Step-by-step explanation:

For x = 2,6

[tex] = 3{x}^{0} [/tex]

[tex] = 3 \times {2,6}^{0} [/tex]

[tex] = 3 \times1 [/tex]

[tex] = 3 [/tex]

[tex] \: [/tex]

For a = -3 and b = -8

[tex] = 10 \times {a}^{2} \times {b}^{0} [/tex]

[tex] = 10 \times {( - 3)}^{2} \times {( - 8)}^{0} [/tex]

[tex] = 10 \times 9 \times 1[/tex]

[tex] = 90[/tex]