when we factor this equation we apply method such that what are two numbers sum of them gives 7 and product of them is 12( let say coefficent of x^2=a, coefficent of x=b and the constant term=c then; to factor this we say two numbers addition of them gives us <b> and product of them gives us <a×c> , so those numbers become 3 and 4 because when we add they give 7 and when we multiply they give 12 .let as factor the equation
the term 7x become 3x+4x
6x^2+3x+4x+2
3x(2x+1)2(2x+1)
we take one of the two equations found in bracket and we place the two terms found out side of the bracket togather in bracket as follows
3x(2x+1)2(2x+1)
(2x+1)(3x+2) this is a factord form of the above equation
