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Mathematics

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need help with pre-cal please

Need Help With Precal Please class=

Answer :

Mhanifago Mhanifago

Answer:

x = n² ± n√(n² + 8)

Step-by-step explanation:

x ≠ 0, n ≠ 0

4/x² + 1/x = 1/(2n²)
(x + 4)/x² = 1/(2n²)
2n²(x + 4) = x²
x² - 2n²x - 8n² = 0
D = (-2n²)² - 4(-8n²) = 4n⁴ + 32n² = 4n²(n² + 8)
x = (2n² ± 2n√(n² + 8))/2
x = n² ± n√(n² + 8)

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