Answer :
[tex]\huge \bf༆ Answer ༄[/tex]
Let's solve for x ~
- [tex] \sf3(11 - 2x) = 27[/tex]
- [tex]\sf33 - 6x = 27[/tex]
- [tex]\sf - 6x = 27 - 33[/tex]
- [tex] - 6x = - 6[/tex]
- [tex]x = - 6 \div - 6[/tex]
- [tex]x = 1[/tex]
Value of x is ~
[tex] \boxed{ \boxed{ \sf \: 1 \: }}[/tex]
[tex]\mathrm{✌ \: Kaul ~✌}[/tex]