Answer :
The heat of fusion of the given sample of the ethyl alcohol is 104.16 J/g.
The given parameters:
- heat required to convert 36.8 g sample of ethyl alcohol, Q = 3.3833 kJ
- mass of the ethyl alcohol, m = 36.8 g
The heat of fusion of the given sample of the ethyl alcohol converted from solid to liquid phase is calculated as follows;
[tex]H_f = \frac{Q}{m} \\\\H_f = \frac{3.833 \times 10^3\ J}{36.8 \ g} \\\\H_f = 104.16 \ J/g[/tex]
Thus, the heat of fusion of the given sample of the ethyl alcohol is 104.16 J/g.
Learn more here:https://brainly.com/question/15950909