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Answer :

Adioabiolago

The equation of the line which is parallel to the line given is; 3y -x = -12

The slope of the line 3y-x=-12 can be evaluated by rearranging the equation to resemble the slope-intercept form of a linear equation as follows;

  • y = (1/3)x -12

The slope of the line is therefore; 1/3;

However, the line parallel to it also has slope; 1/3.

Therefore, the equation of the line as requested is;

  • 1/3 = (y -2)/(x -18)

By Cross-product;

  • 3y -6 = x -18

The equation of the line is therefore;

  • 3y -x = -12.

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