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A 2 kg block slides down a 30 degrees incline as shown above with an acceleration of 2 m/s?
10°
Which of the following correctly indicates the magnitudes of the forces acting up and down the incline?

Answer :

Onyebuchinnajigo

The magnitude of the force acting up and down the incline is 16.97 N.

The given parameters:

  • mass of the block, m = 2 kg
  • inclination of the plane, θ = 30⁰
  • speed of the block, v = 2 m/s

The magnitude of the force acting up and down the incline is calculated as follows;

[tex]\Sigma F = 0 \\\\N - Wcos(\theta) = 0[/tex]

where;

N is the normal reaction, acting upwards

W is the weight of the block, acting downwards

[tex]N = W cos (\theta)\\\\N = mg \ cos(\theta)\\\\N = 2 \times 9.8 \times cos(30)\\\\N = 16.97 \ N[/tex]

Thus, the magnitude of the force acting up and down the incline is 16.97 N.

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