Answer:
Step-by-step explanation:
Q8:
y= -x+4 (given)
Slope of given the line=-1
For required slope which is passing through (6,5):
Using Point slope form:
[tex]y-y_{1} = m(x-x_{1} )[/tex]
y-5=-1(x-6) (m=-1 because lines are parallel)
y-5=-x+6
x+y-5-6=0
x+y-11=0
Q9:
y=-4x-7
slope of the given line:
m=-4
Slope of required line:
m=1/4
Using Point slope form:
[tex]y-y_{1} = m(x-x_{1} )[/tex]
y+1=1/4(x-8)
4y+4=x-8
x-4y-8-4=0
x-4y-12=0
