[tex]\huge \bf༆ Answer ༄[/tex]
Let's calculate the volume of sphere with :
[tex] \sf \: vol = \dfrac{4}{3} \pi {r}^{3} [/tex]
Now, plug the value of radius (r) and find volume ~
- [tex] \sf \dfrac{4}{3} \times 3.14 \times 2.5 \times 2.5 \times 2.5[/tex]
- [tex] \sf \dfrac{12.56}{3} \times \dfrac{25 \times 25 \times 25}{1000} [/tex]
- [tex] \sf \dfrac{12.56 \times 15625}{3} \times \dfrac{1}{1000} [/tex]
- [tex] \sf \approx65416.67 \times \dfrac{1}{1000} [/tex]
- [tex] \approx65.416[/tex]
The value closest to it is 65.45
Therefore, that's the most appropriate choice ~
[tex] ꧁ \large \rm{kaul} \: ꧂[/tex]
