Answer :
β5(|xβ3|)β5<15
Step 1: Add 5 to both sides.
β5(|xβ3|)β5+5<15+5
β5(|xβ3|)<20
Step 2: Divide both sides by -5.
β5(|xβ3|)
β5
<
20
β5
|xβ3|>β4
Step 3: Solve Absolute Value.
|xβ3|>β4
We know eitherxβ3>β4orxβ3<β(β4)
xβ3>β4(Possibility 1)
xβ3+3>β4+3(Add 3 to both sides)
x>β1
xβ3<β(β4)(Possibility 2)
xβ3<4(Simplify both sides of the inequality)
xβ3+3<4+3(Add 3 to both sides)
x<7
Answer:
x>β1 or x<7