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Answer :

Proof:-

In ∆XYZ and ∆VWZ

[tex]\because\sf\begin{cases}\sf XZ\cong VZ(Given)\\ \sf YZ\cong WZ(Given)\\ \sf <XZY\cong <WZV(Opposite angles)\end{cases}[/tex]

Hence

∆XYZ[tex]\cong[/tex]∆VWZ(Side-Angle-Side)

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