Answer:
Step-by-step explanation:
f(x) = x² - 3x + 2
y = x² - 3x + 2
solve for x as a function of y
y - 2 = x² - 3x
complete the square by adding the square of half the x¹ coefficient to each side of the equation.
y - 2 + (-1.5)² = x² - 3x + (-1.5)²
y + 0.25 = (x - 1.5)²
[tex]\sqrt{y + 0.25}[/tex] = x - 1.5
x = 1.5 ± [tex]\sqrt{y + 0.25}[/tex]
now swap the x and y variables and revert to function notation
f(x) = 1.5 ± [tex]\sqrt{x + 0.25}[/tex] domain is x ≥ -0.25
each input will have two outputs except where f(-0.25) = 1.5
