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Answer :

Answer:

(x+1)(xβˆ’2)(x+3)(xβˆ’4)

Apply the distributive property by multiplying each term of x+1 by each term of xβˆ’2.

(x  

2

βˆ’2x+xβˆ’2)(x+3)(xβˆ’4)

Combine βˆ’2x and x to get βˆ’x.

(x  

2

βˆ’xβˆ’2)(x+3)(xβˆ’4)

Apply the distributive property by multiplying each term of x  

2

βˆ’xβˆ’2 by each term of x+3.

(x  

3

+3x  

2

βˆ’x  

2

βˆ’3xβˆ’2xβˆ’6)(xβˆ’4)

Combine 3x  

2

 and βˆ’x  

2

 to get 2x  

2

.

(x  

3

+2x  

2

βˆ’3xβˆ’2xβˆ’6)(xβˆ’4)

Combine βˆ’3x and βˆ’2x to get βˆ’5x.

(x  

3

+2x  

2

βˆ’5xβˆ’6)(xβˆ’4)

Apply the distributive property by multiplying each term of x  

3

+2x  

2

βˆ’5xβˆ’6 by each term of xβˆ’4.

x  

4

βˆ’4x  

3

+2x  

3

βˆ’8x  

2

βˆ’5x  

2

+20xβˆ’6x+24

Combine βˆ’4x  

3

 and 2x  

3

 to get βˆ’2x  

3

.

x  

4

βˆ’2x  

3

βˆ’8x  

2

βˆ’5x  

2

+20xβˆ’6x+24

Combine βˆ’8x  

2

 and βˆ’5x  

2

 to get βˆ’13x  

2

.

x  

4

βˆ’2x  

3

βˆ’13x  

2

+20xβˆ’6x+24

Combine 20x and βˆ’6x to get 14x.

x  

4

βˆ’2x  

3

βˆ’13x  

2

+14x+24

Step-by-step explanation:

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