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Bismawaheed01go
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A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.

a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?​

Answer :

Jporlovebestgo

Answer:u=350m/sec

v=0m/sec

t=0.005sec

a=v-u/t

=0-350/0.005

= -350/0.005

= -350×1000/5

= -70×1000

= -70000 m/sec^2

Explanation: i think this will help you thankyou

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